A magnetic dipole is acted upon by two magnetic fields which are inclined to each other at an angle of 75o . One of the fields has a magnitude of 15 mT . The dipole attains stable equilibrium at an angle of 30o with this field. The magnitude of the other field (in mT ) is close to

Question

A magnetic dipole is acted upon by two magnetic fields which are inclined to each other at an angle of 75o . One of the fields has a magnitude of 15 mT . The dipole attains stable equilibrium at an angle of 30o with this field. The magnitude of the other field (in mT ) is close to (A) 1 (B) 11 (C) 36 (D) 1060

Tardigrade Admin · Accepted Answer

θ 1 + θ = 75o MB1 sinθ 1=MB2 sinθ ⇒ (B1/√2)=(15/2) ⇒ B1=(15/√2)≈11 mT

$1$

$11$

$36$

$1060$

$θ_{1} + θ = 7 5^{o}$
$M B_{1} sin θ_{1} = M B_{2} sin θ$
$\Rightarrow \frac{B _{1}}{2} = \frac{15}{2}$
$\Rightarrow B_{1} = \frac{15}{2} \approx 11 m T$

Q. A magnetic dipole is acted upon by two magnetic fields which are inclined to each other at an angle of 75o . One of the fields has a magnitude of 15mT . The dipole attains stable equilibrium at an angle of 30o with this field. The magnitude of the other field (in mT ) is close to

1

11

36

1060

θ1​+θ=75o MB1​sinθ1​=MB2​sinθ ⇒2​B1​​=215​ ⇒B1​=2​15​≈11mT

$1$

$11$

$36$

$1060$

$θ_{1} + θ = 7 5^{o}$
$M B_{1} sin θ_{1} = M B_{2} sin θ$
$\Rightarrow \frac{B _{1}}{2} = \frac{15}{2}$
$\Rightarrow B_{1} = \frac{15}{2} \approx 11 m T$