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Tardigrade
Question
Mathematics
A.M . of the series 1, 3, 9, 27, dots, 3n is
Q.
A
.
M
. of the series
1
,
3
,
9
,
27
,
…
,
3
n
is
1809
255
Statistics
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A
n
3
n
−
1
12%
B
n
+
1
3
n
+
1
+
1
35%
C
2
(
n
+
1
)
3
n
+
1
−
1
24%
D
n
+
1
3
n
+
1
28%
Solution:
A
.
M
.
=
n
+
1
1
+
3
+
9
+
27
+
…
+
3
n
=
(
3
−
1
)
(
n
+
1
)
1
(
3
n
+
1
−
1
)
(As number of items are n + 1)
=
2
(
n
+
1
)
3
n
+
1
−
1