A luminous body radiates energy at a rate 3.6 × 1028 J/s, then loss of mass of the body per second is

Question

A luminous body radiates energy at a rate 3.6 × 1028 J/s, then loss of mass of the body per second is (A) 2 × 103 kg / s (B) 3 × 104 kg / s (C) 4 × 1011 kg / s (D) 5 × 105 kg / s

Tardigrade Admin · Accepted Answer

Energy and mass are related by the relation E = mc2 Differentiating, we get (dE/dt) = m × [0] + c2 (dm/dt) ⇒ 3.6 × 1028 = 9 × 1016 (dm/dt) ⇒ (dm/dt) = 4 × 1011 kg/s

Q. A luminous body radiates energy at a rate $3.6 \times 1 0^{28}$ J/s, then loss of mass of the body per second is

$2 \times 1 0^{3} k g / s$

$3 \times 1 0^{4} k g / s$

$4 \times 1 0^{11} k g / s$

$5 \times 1 0^{5} k g / s$

Energy and mass are related by the relation
$E = m c^{2}$
Differentiating, we get
$\frac{d E}{d t} = m \times [0] + c^{2} \frac{d m}{d t}$
$\Rightarrow 3.6 \times 1 0^{28} = 9 \times 1 0^{16} \frac{d m}{d t}$
$\Rightarrow \frac{d m}{d t} = 4 \times 1 0^{11} k g / s$

Q. A luminous body radiates energy at a rate 3.6×1028 J/s, then loss of mass of the body per second is

2×103kg/s

3×104kg/s

4×1011kg/s

5×105kg/s