A loop ABCD is moving with velocity v towards the right. The magnetic field is 2 T . Loop is connected to a resistance of 9 Ω . If the steady current of 2 A flows in the loop, then the value of v , if loop has resistance of 4 Ω , is (Given AD = 30 cm )

Question

A loop ABCD is moving with velocity v towards the right. The magnetic field is 2 T . Loop is connected to a resistance of 9 Ω . If the steady current of 2 A flows in the loop, then the value of v , if loop has resistance of 4 Ω , is (Given AD = 30 cm ) <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-hvs8ircegzuq.png" /> (A) 86.7ms- 1 (B) 30ms- 1 (C) 33.33ms- 1 (D) 20ms- 1

Tardigrade Admin · Accepted Answer

When a straight conductor moves with velocity v perpendicular to the magnetic field then emf induced is given by

V = B v l

. Here, it will be

V = B v (l s in θ)

.
Potential difference is

V = B v (l s in θ)

V = 2 \times v \times \frac{30}{100} \times \frac{1}{2} = 0 \cdot 3 v

Now,

Current = \frac{V}{R}

\Rightarrow 2 = \frac{0 \cdot 3 V}{13}

\Rightarrow v = 86.7 m s^{- 1}

Q. A loop $A BC D$ is moving with velocity $v$ towards the right. The magnetic field is $2 T$ . Loop is connected to a resistance of $9 Ω$ . If the steady current of $2 A$ flows in the loop, then the value of $v$ , if loop has resistance of $4 Ω$ , is (Given $A D = 30 c m$ )

$86.7 m s^{- 1}$

$30 m s^{- 1}$

$33.33 m s^{- 1}$

$20 m s^{- 1}$

Q. A loop ABCD is moving with velocity v towards the right. The magnetic field is 2T . Loop is connected to a resistance of 9Ω . If the steady current of 2A flows in the loop, then the value of v , if loop has resistance of 4Ω , is (Given AD=30cm )

86.7ms−1

30ms−1

33.33ms−1

20ms−1

When a straight conductor moves with velocity v perpendicular to the magnetic field then emf induced is given by V=Bvl . Here, it will be V=Bv(lsinθ) . Potential difference is V=Bv(lsinθ) V=2×v×10030​×21​=0⋅3v Now, Current=RV​ ⇒2=130⋅3V​ ⇒v=86.7 m s−1

Q. A loop $A BC D$ is moving with velocity $v$ towards the right. The magnetic field is $2 T$ . Loop is connected to a resistance of $9 Ω$ . If the steady current of $2 A$ flows in the loop, then the value of $v$ , if loop has resistance of $4 Ω$ , is (Given $A D = 30 c m$ )

$86.7 m s^{- 1}$

$30 m s^{- 1}$

$33.33 m s^{- 1}$

$20 m s^{- 1}$