A long straight wire carries 10 A d.c. current an electron travels perpendicular to the plane of this wire at a distance 0.1 m with velocity 5.0 ×106 m s-1. Force acting on the electron due to current in wire is

Question

A long straight wire carries 10 A d.c. current an electron travels perpendicular to the plane of this wire at a distance 0.1 m with velocity 5.0 ×106 m s-1. Force acting on the electron due to current in wire is (A) zero N (B) 0.6 ×10-17 N (C) 2.4 ×10-17 N (D) 2.2 ×10-17 N

Tardigrade Admin · Accepted Answer

Force on the electron vecF=-e( vecv × vecB). As electron is travelling in a plane perpendicular to the plane of wire, so angle θ between vecv and vecB is either 0° or 180° and sin 0° or sin 180°=0.

Q. A long straight wire carries $10 A d . c$ . current an electron travels perpendicular to the plane of this wire at a distance $0.1 m$ with velocity $5.0 \times 1 0^{6} m s^{- 1}$ . Force acting on the electron due to current in wire is

zero N

$0.6 \times 1 0^{- 17} N$

$2.4 \times 1 0^{- 17} N$

$2.2 \times 1 0^{- 17} N$

Force on the electron $F = - e (v \times B)$ . As electron is travelling in a plane perpendicular to the plane of wire, so angle $θ$ between $v$ and $B$ is either $0^{\circ}$ or $18 0^{\circ}$ and $sin 0^{\circ}$ or $sin 18 0^{\circ} = 0$ .

Q. A long straight wire carries 10Ad.c. current an electron travels perpendicular to the plane of this wire at a distance 0.1m with velocity 5.0×106ms−1. Force acting on the electron due to current in wire is

zero N

0.6×10−17N

2.4×10−17N

2.2×10−17N

Force on the electron F=−e(v×B). As electron is travelling in a plane perpendicular to the plane of wire, so angle θ between v and B is either 0∘ or 180∘ and sin0∘ or sin180∘=0.

Q. A long straight wire carries $10 A d . c$ . current an electron travels perpendicular to the plane of this wire at a distance $0.1 m$ with velocity $5.0 \times 1 0^{6} m s^{- 1}$ . Force acting on the electron due to current in wire is

$0.6 \times 1 0^{- 17} N$

$2.4 \times 1 0^{- 17} N$

$2.2 \times 1 0^{- 17} N$

Force on the electron $F = - e (v \times B)$ . As electron is travelling in a plane perpendicular to the plane of wire, so angle $θ$ between $v$ and $B$ is either $0^{\circ}$ or $18 0^{\circ}$ and $sin 0^{\circ}$ or $sin 18 0^{\circ} = 0$ .