A long, straight, hollow conductor tube carrying a current has two sections A and C of unequal cross section joined by a conical section B.1,2 and 3 are the points on a line parallel to the axis of the conductor. The magnetic fields at 1,2 and 3 have magnitude B1,B2 and B3:

Question

A long, straight, hollow conductor tube carrying a current has two sections A and C of unequal cross section joined by a conical section B.1,2 and 3 are the points on a line parallel to the axis of the conductor. The magnetic fields at 1,2 and 3 have magnitude B1,B2 and B3: Question

(A) B1=B2=B3 (B) B1=B2≠ B3 (C) B1 < B2 < B3 (D) B1>B2>B3

Tardigrade Admin · Accepted Answer

Current not depends on area of cross section of wire So IA=IB=IC=I and B propto I . Hence, B1=B2=B3

$B_{1} = B_{2} = B_{3}$

$B_{1} = B_{2} \neq = B_{3}$

$B_{1} < B_{2} < B_{3}$

$B_{1} > B_{2} > B_{3}$

Current not depends on area of cross section of wire
So $I_{A} = I_{B} = I_{C} = I$ and $B \propto I$ .
Hence, $B_{1} = B_{2} = B_{3}$

Q. A long, straight, hollow conductor tube carrying a current has two sections A and C of unequal cross section joined by a conical section B.1,2 and 3 are the points on a line parallel to the axis of the conductor. The magnetic fields at 1,2 and 3 have magnitude B1​,B2​ and B3​:

B1​=B2​=B3​

B1​=B2​=B3​

B1​<B2​<B3​

B1​>B2​>B3​

Current not depends on area of cross section of wire So IA​=IB​=IC​=I and B∝I . Hence, B1​=B2​=B3​

$B_{1} = B_{2} = B_{3}$

$B_{1} = B_{2} \neq = B_{3}$

$B_{1} < B_{2} < B_{3}$

$B_{1} > B_{2} > B_{3}$

Current not depends on area of cross section of wire
So $I_{A} = I_{B} = I_{C} = I$ and $B \propto I$ .
Hence, $B_{1} = B_{2} = B_{3}$