A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved the new value of the magnetic field is

Question

A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved the new value of the magnetic field is (A) B/2 (B) B (C) 2 B (D) 4 B

Tardigrade Admin · Accepted Answer

Magnetic field induction at point inside the solenoid of length l, having n turns per unit length carrying current i is given by B=μ0 n i If i arrow doubled, n arrow halved then B arrow remains same.

Q. A long solenoid carrying a current produces a magnetic field $B$ along its axis. If the current is doubled and the number of turns per cm is halved the new value of the magnetic field is

B/2

B

2 B

4 B

Magnetic field induction at point inside the solenoid of length $l$ , having $n$ turns per unit length carrying current $i$ is given by
$B = μ_{0} ni$
If $i \to$ doubled, $n \to$ halved then $B \to$ remains same.

Q. A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved the new value of the magnetic field is

B/2

B

2 B

4 B

Magnetic field induction at point inside the solenoid of length l, having n turns per unit length carrying current i is given by B=μ0​ni If i→ doubled, n→ halved then B→ remains same.

Q. A long solenoid carrying a current produces a magnetic field $B$ along its axis. If the current is doubled and the number of turns per cm is halved the new value of the magnetic field is

Magnetic field induction at point inside the solenoid of length $l$ , having $n$ turns per unit length carrying current $i$ is given by
$B = μ_{0} ni$
If $i \to$ doubled, $n \to$ halved then $B \to$ remains same.