A locomotive accelerates a train of identical railway carts. The carts are numbered consequently with the cart next to locomotive having the number 1 . The tension in the connection between the carts with number 4 and 5 is three times bigger than the tension in the connection between the carts with numbers 14 and 15. What's the number of the last cart?

Question

A locomotive accelerates a train of identical railway carts. The carts are numbered consequently with the cart next to locomotive having the number 1 . The tension in the connection between the carts with number 4 and 5 is three times bigger than the tension in the connection between the carts with numbers 14 and 15. What's the number of the last cart? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/9ddd93367718177f5a69b7890a21be06-.png" /> T1=3 T2 T propto m T2 propto x T1 propto x+10 (1/3)=(x/x+10) x+10=3 x 2 x=10 x=5 5 carts so last number is (19)

T1​=3T2​ T∝m T2​∝x T1​∝x+10 31​=x+10x​ x+10=3x 2x=10 x=5 5 carts so last number is (19)

$T_{1} = 3 T_{2}$
$T \propto m$
$T_{2} \propto x$
$T_{1} \propto x + 10$
$\frac{1}{3} = \frac{x}{x + 10}$
$x + 10 = 3 x$
$2 x = 10$
$x = 5$
$5$ carts so last number is $(19)$