A liquid X of density 3.36 text g/cm3 is poured in a U-tube, which contains Hg. Another liquid Y is poured in left arm with height 8 cm, upper levels of X and Y are same. What is the density of Y?

Question

A liquid X of density 3.36 text g/cm3 is poured in a U-tube, which contains Hg. Another liquid Y is poured in left arm with height 8 cm, upper levels of X and Y are same. What is the density of Y? (A) 0.8 g/cc (B) 1.2 g/cc (C) 1.4 g/cc (D) 1.6 g/cc

Tardigrade Admin · Accepted Answer

As shown in figure, in the two arms of a tube pressure remains same on surface

P P^{'}

. Hence,

8 \times ρ_{Y} \times g + 2 \times ρ_{H g} \times g

= 10 \times ρ_{X} \times g

∴ 8 ρ_{Y} + 2 \times 13.6 = 10 \times 3.36

or

ρ_{Y} = \frac{33.6 - 27.2}{8}

= 0.8 g / cc

Q. A liquid X of density 3.36g/cm3 is poured in a U-tube, which contains Hg. Another liquid Y is poured in left arm with height 8cm, upper levels of X and Y are same. What is the density of Y?

0.8 g/cc

1.2 g/cc

1.4 g/cc

1.6 g/cc

As shown in figure, in the two arms of a tube pressure remains same on surface PP′. Hence, 8×ρY​×g+2×ρHg​×g =10×ρX​×g ∴8ρY​+2×13.6=10×3.36 or ρY​=833.6−27.2​ =0.8g/cc

Q. A liquid $X$ of density $3.36 g / c m^{3}$ is poured in a U-tube, which contains $H g$ . Another liquid $Y$ is poured in left arm with height $8 c m$ , upper levels of $X$ and $Y$ are same. What is the density of $Y$ ?

As shown in figure, in the two arms of a tube pressure remains same on surface $P P^{'}$ . Hence,
$8 \times ρ_{Y} \times g + 2 \times ρ_{H g} \times g$
$= 10 \times ρ_{X} \times g$

$∴ 8 ρ_{Y} + 2 \times 13.6 = 10 \times 3.36$
or $ρ_{Y} = \frac{33.6 - 27.2}{8}$
$= 0.8 g / cc$