Q.
A liquid haying area of free surface A has an orifice at a depth h with an area a, below the liquid surface, then the velocity ν of flow through the orifice is:
2281
236
Mechanical Properties of Fluids
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Solution:
Applying Bernoulli's theorem,
ρP+21(ν′)2+gh=ρP+21ν2+0
where ν′ is velocity of all surfaces ofliquid and V is velocity of efflux. From equation of continuity
Aν′=aν⇒ν′=Aaν ∴21(Aaν)2+gh=21ν2⇒ν=2gh(A2−a2A2)