A liquid flows in the tube from left to right as shown in figure. A1 and A2 are the cross-sections of the portions of the tube as shown. The ratio of speed (v1/v2) will be

Question

A liquid flows in the tube from left to right as shown in figure. A1 and A2 are the cross-sections of the portions of the tube as shown. The ratio of speed (v1/v2) will be (A) (A1/A2) (B) (A2/A1) (C) √(A2/A1) (D) √(A1/A2)

Tardigrade Admin · Accepted Answer

By equation of continuity v1 A1=v2 A2 So, (v1/v2)=(A2/A1)

Q. A liquid flows in the tube from left to right as shown in figure. $A_{1}$ and $A_{2}$ are the cross-sections of the portions of the tube as shown. The ratio of speed $\frac{v _{1}}{v _{2}}$ will be

$\frac{A _{1}}{A _{2}}$

$\frac{A _{2}}{A _{1}}$

$\frac{A _{2}}{A _{1}}$

$\frac{A _{1}}{A _{2}}$

By equation of continuity
$v_{1} A_{1} = v_{2} A_{2}$
So, $\frac{v _{1}}{v _{2}} = \frac{A _{2}}{A _{1}}$

Q. A liquid flows in the tube from left to right as shown in figure. A1​ and A2​ are the cross-sections of the portions of the tube as shown. The ratio of speed v2​v1​​ will be

A2​A1​​

A1​A2​​

A1​A2​​​

A2​A1​​​

By equation of continuity v1​A1​=v2​A2​ So, v2​v1​​=A1​A2​​

Q. A liquid flows in the tube from left to right as shown in figure. $A_{1}$ and $A_{2}$ are the cross-sections of the portions of the tube as shown. The ratio of speed $\frac{v _{1}}{v _{2}}$ will be

$\frac{A _{1}}{A _{2}}$

$\frac{A _{2}}{A _{1}}$

$\frac{A _{2}}{A _{1}}$

$\frac{A _{1}}{A _{2}}$

By equation of continuity
$v_{1} A_{1} = v_{2} A_{2}$
So, $\frac{v _{1}}{v _{2}} = \frac{A _{2}}{A _{1}}$