A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture is illuminated normally by a parallel beam of wavelength 5 × 10-5 cm. The distance of the first dark band of the diffraction pattern from the centre of the screen is

Question

A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture is illuminated normally by a parallel beam of wavelength 5 × 10-5 cm. The distance of the first dark band of the diffraction pattern from the centre of the screen is (A) 0.10 cm (B) 0.25 cm (C) 0.20 cm (D) 0.15 cm

Tardigrade Admin · Accepted Answer

x = (5×10-5 ×60/ 0.02) x = (300 ×10-5/0.02) = 0.15 cm

Q. A linear aperture whose width is 0.02cm is placed immediately in front of a lens of focal length 60cm. The aperture is illuminated normally by a parallel beam of wavelength 5×10−5cm. The distance of the first dark band of the diffraction pattern from the centre of the screen is

0.10 cm

0.25 cm

0.20 cm

0.15 cm

x=0.025×10−5×60​ x=0.02300×10−5​=0.15cm

$x = \frac{5 \times 1 0 ^{- 5} \times 60}{0.02}$
$x = \frac{300 \times 1 0 ^{- 5}}{0.02} = 0.15 c m$