A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the blocks is g/8 , then the ratio of the masses is :

Question

A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the blocks is g/8 , then the ratio of the masses is : (A) 8:1 (B) 9:7 (C) 4:3 (D) 5:3

Tardigrade Admin · Accepted Answer

FBD of system <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-oynedzvukjkhppsf.jpg" /> Considering m2>m1 m2g-T=m2a...(i) T-m1g=m1a...(ii) a=((m2 - m1)/m1 + m2)g Given, a=g/8⇒ (g/8)=((m2 - m1/ m1 + m2))g m1+m2=8(m2 - m1) 7m2=9m1 (m2/ m1)=(9/7)

Q. A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the blocks is $g /8$ , then the ratio of the masses is :

$8 : 1$

$9 : 7$

$4 : 3$

$5 : 3$

Q. A light string passing over a smooth light pulley connects two blocks of masses m1​ and m2​ (vertically). If the acceleration of the blocks is g/8 , then the ratio of the masses is :

8:1

9:7

4:3

5:3

FBD of system Considering m2​>m1​ m2​g−T=m2​a...(i) T−m1​g=m1​a...(ii) a=m1​+m2​(m2​−m1​)​g Given, a=g/8⇒8g​=(m1​+m2​m2​−m1​​)g m1​+m2​=8(m2​−m1​) 7m2​=9m1​ m1​m2​​=79​

Q. A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the blocks is $g /8$ , then the ratio of the masses is :

$8 : 1$

$9 : 7$

$4 : 3$

$5 : 3$