A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the system is g /8, then the ratio of the masses is

Question

A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 (vertically). If the acceleration of the system is g /8, then the ratio of the masses is (A) 8: 1 (B) 9: 7 (C) 4: 3 (D) 5: 3

Tardigrade Admin · Accepted Answer

From F.B.D. of m1: T-m1g = m1 a (i) From F.B.D. of m2: m2g -T =m2 a (ii) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5e76353c1ed36d38a4c366f5a7dfc228-.png" /> From (i) and (ii), a =((m2-m1/m1+m2))g ⇒ (g/8)=((m2-m1/m1+m2))g ⇒ (m2/m1)=(9/7)

Q. A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is $g /8$ , then the ratio of the masses is

$8 : 1$

$9 : 7$

$4 : 3$

$5 : 3$

Q. A light string passing over a smooth light pulley connects two blocks of masses m1​ and m2​ (vertically). If the acceleration of the system is g/8, then the ratio of the masses is

8:1

9:7

4:3

5:3

From F.B.D. of m1​:T−m1​g=m1​a ___ (i) From F.B.D. of m2​:m2​g−T=m2​a ___ (ii) From (i) and (ii), a=(m1​+m2​m2​−m1​​)g ⇒8g​=(m1​+m2​m2​−m1​​)g ⇒m1​m2​​=79​

Q. A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is $g /8$ , then the ratio of the masses is

$8 : 1$

$9 : 7$

$4 : 3$

$5 : 3$