A light rope is wound around a hollow cylinder of mass 4 kg and radius 40 cm. If the rope is pulled with a force of 40 N. it's angular acceleration is

Question

A light rope is wound around a hollow cylinder of mass 4 kg and radius 40 cm. If the rope is pulled with a force of 40 N. it's angular acceleration is (A) 0.40 rads-2 (B) 0.25 rads-2 (C) 25 rads-2 (D) 40 rads-2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/dbc3bf3f833dceda6149678dfd43a4d7-.png" /> Torque, τ=I α F × r =M r2 α 40 × 0.4=4 ×(0.4)2 α 16=0.64 α α=(16/0.64) =(16/64) × 100 =25 rad / s 2

Q. A light rope is wound around a hollow cylinder of mass $4 k g$ and radius $40 c m .$ If the rope is pulled with a force of $40 N .$ it's angular acceleration is

$0.40 r a d s^{- 2}$

$0.25 r a d s^{- 2}$

$25 r a d s^{- 2}$

$40 r a d s^{- 2}$

Torque, $τ = I α$
$F \times r = M r^{2} α$
$40 \times 0.4 = 4 \times (0.4)^{2} α$
$16 = 0.64 α$
$α = \frac{16}{0.64}$
$= \frac{16}{64} \times 100$
$= 25 r a d / s^{2}$

Q. A light rope is wound around a hollow cylinder of mass 4kg and radius 40cm. If the rope is pulled with a force of 40N. it's angular acceleration is

0.40rads−2

0.25rads−2

25rads−2

40rads−2