A light ray is incident on a plane mirror M . The mirror is rotated in direction as shown in figure by an arrows at frequency (.(9/π ).) revolution/sec. What will be the speed of the spot on wall when angle of incident becomes 37° given that the light reflected by the mirror is received on the wall W at a distance of 10m .

Question

A light ray is incident on a plane mirror M . The mirror is rotated in direction as shown in figure by an arrows at frequency (.(9/π ).) revolution/sec. What will be the speed of the spot on wall when angle of incident becomes 37° given that the light reflected by the mirror is received on the wall W at a distance of 10m . <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-sr3xbeqrjierbdfo.jpg" /> (A) 10msec- 1 (B) 1000msec- 1 (C) 360msec- 1 (D) 500msec- 1

Tardigrade Admin · Accepted Answer

1=10tan(.90-θ .)(dl/dt)=10(cosec)2θ × ω =500m/sec

$10 m se c^{- 1}$

$1000 m se c^{- 1}$

$360 m se c^{- 1}$

$500 m se c^{- 1}$

$1 = 10 t an (90 - θ) \frac{d l}{d t} = 10 (cosec)^{2} θ \times ω = 500 m / sec$

10msec−1

1000msec−1

360msec−1

500msec−1

1=10tan(90−θ)dtdl​=10(cosec)2θ×ω=500m/sec

$10 m se c^{- 1}$

$1000 m se c^{- 1}$

$360 m se c^{- 1}$

$500 m se c^{- 1}$

$1 = 10 t an (90 - θ) \frac{d l}{d t} = 10 (cosec)^{2} θ \times ω = 500 m / sec$