A light ray emerging from the point source placed at P (1,3) is reflected at a point Q in the x-axis. If the reflected ray passes through the point R(6,7), then the abscissa of Q is

Question

A light ray emerging from the point source placed at P (1,3) is reflected at a point Q in the x-axis. If the reflected ray passes through the point R(6,7), then the abscissa of Q is (A) (5/2) (B) 3 (C) (7/2) (D) 1

Tardigrade Admin · Accepted Answer

∴ ( y +3)=2( x -1) (. Equation of line .P' R ) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/8f1b0582e84c2ebbbfcdef7f72a4fdf4-.png" /> Put y =0, we get x=1+(3/2)=(5/2)

Q. A light ray emerging from the point source placed at $P$ $(1, 3)$ is reflected at a point $Q$ in the $x$ -axis. If the reflected ray passes through the point $R (6, 7)$ , then the abscissa of $Q$ is

$\frac{5}{2}$

$3$

$\frac{7}{2}$

$1$

$∴ (y + 3) = 2 (x - 1)$
$($ Equation of line $P^{'} R)$

Put $y = 0$ , we get
$x = 1 + \frac{3}{2} = \frac{5}{2}$

Q. A light ray emerging from the point source placed at P (1,3) is reflected at a point Q in the x-axis. If the reflected ray passes through the point R(6,7), then the abscissa of Q is

25​

3

27​

1

∴(y+3)=2(x−1) ( Equation of line P′R) Put y=0, we get x=1+23​=25​

Q. A light ray emerging from the point source placed at $P$ $(1, 3)$ is reflected at a point $Q$ in the $x$ -axis. If the reflected ray passes through the point $R (6, 7)$ , then the abscissa of $Q$ is

$\frac{5}{2}$

$3$

$\frac{7}{2}$

$1$

$∴ (y + 3) = 2 (x - 1)$
$($ Equation of line $P^{'} R)$

Put $y = 0$ , we get
$x = 1 + \frac{3}{2} = \frac{5}{2}$