A light ray coming along the line 3x + 4y = 5 gets reflected from the line a x + b y = 1 and goes along the line 5x- 12 y = 10. Then,

Question

A light ray coming along the line 3x + 4y = 5 gets reflected from the line a x + b y = 1 and goes along the line 5x- 12 y = 10. Then, (A) a = 64/115, b=112/15 (B) a = 14/15, b = -8/115 (C) a = 64/115, 6 = -8/115 (D) a = 64/15, b = 14/15

Tardigrade Admin · Accepted Answer

ax + by = 1 will be one of the bisectors of the given line. Equations of bisectors of the given lines are (3x+4y-5/5) = ±((5x-12y-10/13)) or 64 x - 8y = 115 or 14 x + 112 y = 15 or a = (64/115), b = -(8/115) or a = (14/15), b = (12/115)

Q. A light ray coming along the line $3 x + 4 y = 5$ gets reflected from the line $a x + b y = 1$ and goes along the line $5 x - 12 y = 10$ . Then,

$a = 64/115, b = 112/15$

$a = 14/15, b = - 8/115$

$a = 64/115, 6 = - 8/115$

$a = 64/15, b = 14/15$

Q. A light ray coming along the line 3x+4y=5 gets reflected from the line ax+by=1 and goes along the line 5x−12y=10. Then,

a=64/115,b=112/15

a=14/15,b=−8/115

a=64/115,6=−8/115

a=64/15,b=14/15

ax+by=1 will be one of the bisectors of the given line. Equations of bisectors of the given lines are 53x+4y−5​=±(135x−12y−10​) or 64x−8y=115 or 14x+112y=15 or a=11564​,b=−1158​ or a=1514​,b=11512​

Q. A light ray coming along the line $3 x + 4 y = 5$ gets reflected from the line $a x + b y = 1$ and goes along the line $5 x - 12 y = 10$ . Then,

$a = 64/115, b = 112/15$

$a = 14/15, b = - 8/115$

$a = 64/115, 6 = - 8/115$

$a = 64/15, b = 14/15$