A light of wavelength 6000 mathringA in air enters a medium of refractive index 1.5. Inside the medium, its frequency is v and its wavelength is λ. Then,

Question

A light of wavelength 6000 mathringA in air enters a medium of refractive index 1.5. Inside the medium, its frequency is v and its wavelength is λ. Then, (A) v=5 × 1014 Hz (B) v=7.5 × 1014 Hz (C) λ=4000 mathringA  (D) λ=9000 mathringA

Tardigrade Admin · Accepted Answer

Given, λ a =6000 mathringA , ∴ v a =( c /λ a ) =(3 × 108/6000 × 10-10) =5 × 1014 Hz In water, λm=(λ a /μ)=(6000 mathringA /1.5) v m= v a =5 × 1014 Hz

Q. A light of wavelength $6000 \overset{˚}{A}$ in air enters a medium of refractive index $1.5.$ Inside the medium, its frequency is $v$ and its wavelength is $λ$ . Then,

$v = 5 \times 1 0^{14} Hz$

$v = 7.5 \times 1 0^{14} Hz$

$λ = 4000 \overset{˚}{A}$

$λ = 9000 \overset{˚}{A}$

Given, $λ_{a} = 6000 \overset{˚}{A}$ ,
$∴ v_{a} = \frac{c}{λ _{a}}$
$= \frac{3 \times 1 0 ^{8}}{6000 \times 1 0 ^{- 10}}$
$= 5 \times 1 0^{14} Hz$
In water, $λ_{m} = \frac{λ _{a}}{μ} = \frac{6000 A ˚}{1.5}$
$v_{m} = v_{a} = 5 \times 1 0^{14} Hz$

Q. A light of wavelength 6000A˚ in air enters a medium of refractive index 1.5. Inside the medium, its frequency is v and its wavelength is λ. Then,

v=5×1014Hz

v=7.5×1014Hz

λ=4000A˚

λ=9000A˚