A light of wavelength 6000 A in air enters a medium of refractive index 1.5. Inside the medium, its frequency is v and its wavelength is λ (1) v=5× 1014Hz (2) v=7.5× 1014Hz (3) λ =4000 AA (4) λ =9000 AA

Question

A light of wavelength 6000 A in air enters a medium of refractive index 1.5. Inside the medium, its frequency is v and its wavelength is λ (1) v=5× 1014Hz (2) v=7.5× 1014Hz (3) λ =4000 AA (4) λ =9000 AA  (A) 1, 2 and 3 are correct (B) 1 and 2 are correct (C) 2 and 4 are correct (D) 1 and 3 are correct

Tardigrade Admin · Accepted Answer

λ a=6000 va=(c/λ a)=(3× 108/6000× 10-10) =5× 1014Hz In water, λ m=(λ a/μ )=(6000/1.5)=4000

Q. A light of wavelength 6000 A in air enters a medium of refractive index 1.5. Inside the medium, its frequency is v and its wavelength is $λ$ (1) $v = 5 \times 10^{14} Hz$ (2) $v = 7.5 \times 10^{14} Hz$ (3) $λ = 4000 \overset{˚}{A}$ (4) $λ = 9000 \overset{˚}{A}$

1, 2 and 3 are correct

1 and 2 are correct

2 and 4 are correct

1 and 3 are correct

$λ_{a} = 6000$
$v_{a} = \frac{c}{λ _{a}} = \frac{3 \times 10 ^{8}}{6000 \times 10 ^{- 10}}$
$= 5 \times 10^{14} Hz$
In water, $λ_{m} = \frac{λ _{a}}{μ} = \frac{6000}{1.5} = 4000$

Q. A light of wavelength 6000 A in air enters a medium of refractive index 1.5. Inside the medium, its frequency is v and its wavelength is λ (1) v=5×1014Hz (2) v=7.5×1014Hz (3) λ=4000A˚ (4) λ=9000A˚