A lift is going up. The variation in the speed of the lift is as given in the graph. What is the height to which the lift takes the passengers?

Question

A lift is going up. The variation in the speed of the lift is as given in the graph. What is the height to which the lift takes the passengers? (A) 3.6 m (B) 28.8 m (C) 36.0 m (D) Cannot be calculated from the above graph

Tardigrade Admin · Accepted Answer

Area of trapezium =(1/2) × 3.6×(12 + 8) = 36.0 m

Q. A lift is going up. The variation in the speed of the lift is as given in the graph. What is the height to which the lift takes the passengers?

3.6 m

28.8 m

36.0 m

Cannot be calculated from the above graph

Area of trapezium $= \frac{1}{2} \times 3.6 \times (12 + 8) = 36.0 m$

Q. A lift is going up. The variation in the speed of the lift is as given in the graph. What is the height to which the lift takes the passengers?

3.6 m

28.8 m

36.0 m

Cannot be calculated from the above graph

Area of trapezium =21​×3.6×(12+8)=36.0m

Area of trapezium $= \frac{1}{2} \times 3.6 \times (12 + 8) = 36.0 m$