A lens of power +3.5 diopters is placed in contact with a lens of power -2.5 diopter. The combination will behave like:

Question

A lens of power +3.5 diopters is placed in contact with a lens of power -2.5 diopter. The combination will behave like: (A) A convergent lens of focal length 100 cm (B) A divergent lens of focal length 100 cm (C) A convergent lens of focal 200 cm (D) A divergent lens of focal length 200 cm

Tardigrade Admin · Accepted Answer

P = P 1+ P 2=+2-1=+1 diopter, lens behaves as convergent F =(1/ P )=(1/1)=1 m =100 cm

Q. A lens of power +3.5 diopters is placed in contact with a lens of power -2.5 diopter. The combination will behave like:

A convergent lens of focal length 100 cm

A divergent lens of focal length 100 cm

A convergent lens of focal 200 cm

A divergent lens of focal length 200 cm

$P = P_{1} + P_{2} = + 2 - 1 = + 1$ diopter, lens behaves as convergent $< b r / > F = \frac{1}{P} = \frac{1}{1} = 1 m = 100 c m < b r / >$

Q. A lens of power +3.5 diopters is placed in contact with a lens of power -2.5 diopter. The combination will behave like:

A convergent lens of focal length 100 cm

A divergent lens of focal length 100 cm

A convergent lens of focal 200 cm

A divergent lens of focal length 200 cm

P=P1​+P2​=+2−1=+1 diopter, lens behaves as convergent <br/>F=P1​=11​=1m=100cm<br/>

$P = P_{1} + P_{2} = + 2 - 1 = + 1$ diopter, lens behaves as convergent $< b r / > F = \frac{1}{P} = \frac{1}{1} = 1 m = 100 c m < b r / >$