A large parallel plate capacitor, whose plates have an area of 1 m 2 are separated from each other by 1 . mm, is being charged at a rate of 25.8 V / s. If the dielectric between the plates has the dielectric constant 10, then the displacement current at this instant is

Question

A large parallel plate capacitor, whose plates have an area of 1 m 2 are separated from each other by 1 . mm, is being charged at a rate of 25.8 V / s. If the dielectric between the plates has the dielectric constant 10, then the displacement current at this instant is (A) 25 μ A (B) 11 μ A (C) 2.2 μ A (D) 1.1 μ A

Tardigrade Admin · Accepted Answer

C=(ε0 K A/d) =((8.85 × 10-12) × 10 × 1/10-3) =8.85 × 10-8 F i=(d/d t)(C V) =C (d V/d t) =8.85 × 10-8 × 25 =2.2 × 10-6 A =2.2 μ A

Q. A large parallel plate capacitor, whose plates have an area of $1 m^{2}$ are separated from each other by $1. mm$ , is being charged at a rate of $25.8 V / s$ . If the dielectric between the plates has the dielectric constant $10$ , then the displacement current at this instant is

$25 μ A$

$11 μ A$

$2.2 μ A$

$1.1 μ A$

$C = \frac{ε _{0} K A}{d}$
$= \frac{( 8.85 \times 1 0 ^{- 12} ) \times 10 \times 1}{1 0 ^{- 3}}$
$= 8.85 \times 1 0^{- 8} F$
$i = \frac{d}{d t} (C V) = C \frac{d V}{d t}$
$= 8.85 \times 1 0^{- 8} \times 25$
$= 2.2 \times 1 0^{- 6} A$
$= 2.2 μ A$

Q. A large parallel plate capacitor, whose plates have an area of 1m2 are separated from each other by 1.mm, is being charged at a rate of 25.8V/s. If the dielectric between the plates has the dielectric constant 10, then the displacement current at this instant is

25μA

11μA

2.2μA

1.1μA