A juggler throws balls into air. He throws one when ever the previous one is at its highest point. If he throws n balls each second, the height to which each ball will rise is

Question

A juggler throws balls into air. He throws one when ever the previous one is at its highest point. If he throws n balls each second, the height to which each ball will rise is (A)  (g/2n2)  (B)  (2g/n2)  (C)  (2g/n)  (D)  (g/4n2)

Tardigrade Admin · Accepted Answer

Time taken by each ball to reach highest point,

t = \frac{1}{n}

second.
As the juggler throws the second ball, when the first ball is at its highest point, so

v = 0

Using

v = u + a t

, we have

0 = u + (- g) (1/ n)

or

u = (g / n)

. Also,

v^{2} = u^{2} + 2 a s

∴ 0 = (g / n^{2}) + 2 (- g) h

or

h = \frac{g}{2 n ^{2}}

Q. A juggler throws balls into air. He throws one when ever the previous one is at its highest point. If he throws $n$ balls each second, the height to which each ball will rise is

$\frac{g}{2 n ^{2}}$

$\frac{2 g}{n ^{2}}$

$\frac{2 g}{n}$

$\frac{g}{4 n ^{2}}$

Q. A juggler throws balls into air. He throws one when ever the previous one is at its highest point. If he throws n balls each second, the height to which each ball will rise is

2n2g​

n22g​

n2g​

4n2g​

Time taken by each ball to reach highest point, t=n1​ second. As the juggler throws the second ball, when the first ball is at its highest point, so v=0 Using v=u+at , we have 0=u+(−g)(1/n) or u=(g/n) . Also, v2=u2+2as ∴0=(g/n2)+2(−g)h or h=2n2g​

Q. A juggler throws balls into air. He throws one when ever the previous one is at its highest point. If he throws $n$ balls each second, the height to which each ball will rise is

$\frac{g}{2 n ^{2}}$

$\frac{2 g}{n ^{2}}$

$\frac{2 g}{n}$

$\frac{g}{4 n ^{2}}$