A is a lighter phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by using a solution of

Question

A is a lighter phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by using a solution of (A) sodium hydroxide (B) sodium sulphate (C) calcium chloride (D) sodium bicarbonate

Tardigrade Admin · Accepted Answer

Carboxylic acids are soluble in sodium
bicarbonate but phenol are not dissolve in it, so they
are separated because carboxylic acid react with
NaHCO

_{3}

and form sodium carboxylate.

R - COO H + N a H C O_{3} \to R - COON a

+ H_{2} C O_{3}

Q. A is a lighter phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by using a solution of

sodium hydroxide

sodium sulphate

calcium chloride

sodium bicarbonate

Carboxylic acids are soluble in sodium bicarbonate but phenol are not dissolve in it, so they are separated because carboxylic acid react with NaHCO3​ and form sodium carboxylate. R−COOH+NaHCO3​→R−COONa +H2​CO3​

Q. A is a lighter phenol and B is an aromatic
carboxylic acid. Separation of a mixture of A
and B can be carried out easily by using a
solution of

Carboxylic acids are soluble in sodium
bicarbonate but phenol are not dissolve in it, so they
are separated because carboxylic acid react with
NaHCO $_{3}$ and form sodium carboxylate.
$R - COO H + N a H C O_{3} \to R - COON a$
$+ H_{2} C O_{3}$