a+i b c+i d can be explained only when

Question

a+i b >c+i d can be explained only when (A) b=0, c=0 (B) b=0, d=0 (C) a=0, c=0 (D) a=0, d=0

Tardigrade Admin · Accepted Answer

Two complex numbers are either equal or not equal. Comparison of complex numbers is not possible i.e., inequality does not exist for complex numbers.
: If

a + ib > c + i d

this comparision is only possible when it is purely real.
Hence,

b = d = 0

.

Q. $a + ib > c + i d$ can be explained only when

$b = 0, c = 0$

$b = 0, d = 0$

$a = 0, c = 0$

$a = 0, d = 0$

Two complex numbers are either equal or not equal. Comparison of complex numbers is not possible i.e., inequality does not exist for complex numbers.
: If $a + ib > c + i d$ this comparision is only possible when it is purely real.
Hence, $b = d = 0$ .

Q. a+ib>c+id can be explained only when

b=0,c=0

b=0,d=0

a=0,c=0

a=0,d=0