A hydrogen-like atom in ground state absorbs n photons having the same energy and its emits exactly n photons when electrons transition takes placed. Then, the energy of the absorbed photon may be

Question

A hydrogen-like atom in ground state absorbs n photons having the same energy and its emits exactly n photons when electrons transition takes placed. Then, the energy of the absorbed photon may be (A) 91.8 eV (B) 40.8 eV (C) 48.4 eV (D) 54.4 eV

Tardigrade Admin · Accepted Answer

Exp: Number of dark lines (in absorption), i.e., excitation = Number of bright lines (in emission), i.e.,

d e

-excitation
It is possible only when the

e^{-}

is excited to

n = 2

from ground state
Clearly,

Δ E = 91.8 e V

and

40.8 e V

are possible

(L i^{2 +}) (H e^{\oplus})

Q. A hydrogen-like atom in ground state absorbs $n$ photons having the same energy and its emits exactly $n$ photons when electrons transition takes placed. Then, the energy of the absorbed photon may be

$91.8 e V$

$40.8 e V$

$48.4 e V$

$54.4 e V$

Exp: Number of dark lines (in absorption), i.e., excitation = Number of bright lines (in emission), i.e., $d e$ -excitation
It is possible only when the $e^{-}$ is excited to $n = 2$ from ground state
Clearly, $Δ E = 91.8 e V$ and $40.8 e V$ are possible
$(L i^{2 +}) (H e^{\oplus})$

Q. A hydrogen-like atom in ground state absorbs n photons having the same energy and its emits exactly n photons when electrons transition takes placed. Then, the energy of the absorbed photon may be

91.8eV

40.8eV

48.4eV

54.4eV