A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by

Question

A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by (A) 3.16 × 10−34 Js (B) 1.05 × 10−34 Js (C) 4.22 × 10−34 Js (D) 2.11 × 10−34 Js

Tardigrade Admin · Accepted Answer

By absorbing 10.2ev, electron goes to 2nd orbit as En=(-13.6/n2) ev, E1=-13.6 e V E2=-3.4 e V E2-E1=10.2 e V L2-L1=(n2 h/2 π)-(n 1h/2 π)=(2 h/2 π)-(h/2 π)=(6.62×10-34/2×3.14)=1.05×10-34 J S

Q. A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by

$3.16 \times 1 0^{- 34}$ Js

$1.05 \times 1 0^{- 34}$ Js

$4.22 \times 1 0^{- 34}$ Js

$2.11 \times 1 0^{- 34}$ Js

Q. A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by

3.16×10−34 Js

1.05×10−34 Js

4.22×10−34 Js

2.11×10−34 Js

By absorbing 10.2ev, electron goes to 2ndorbitasEn=n2−13.6​ev, E1​=−13.6eV E2​=−3.4eV E2​−E1​=10.2eV L2​−L1​=2πn2​h​−2πn1​h​=2π2h​−2πh​=2×3.146.62×10−34​=1.05×10−34JS

$3.16 \times 1 0^{- 34}$ Js

$1.05 \times 1 0^{- 34}$ Js

$4.22 \times 1 0^{- 34}$ Js

$2.11 \times 1 0^{- 34}$ Js