A hydrocarbon of molecular formula C 7 H 12 on catalytic hydrogenation over platinum gives C 7 H 16. The parent hydrocarbon adds bromine and also reacts with [ Ag ( NH 3)2] OH to give a precipitate. The parent hydrocarbon is

Question

A hydrocarbon of molecular formula C 7 H 12 on catalytic hydrogenation over platinum gives C 7 H 16. The parent hydrocarbon adds bromine and also reacts with [ Ag ( NH 3)2] OH to give a precipitate. The parent hydrocarbon is (A) ( CH 3)3 CCH 2 C ≡ CH (B) CH 3 CH = CHCH 2 CH = CH 2 (C) CH 3 CH 2 C ≡ CHCH ( CH 3)2 (D) CH 3 CH = CHCH = CHCH 3

Tardigrade Admin · Accepted Answer

Correct answer is (a) ( CH 3)3 CCH 2 C ≡ CH

Q. A hydrocarbon of molecular formula $C_{7} H_{12}$ on catalytic hydrogenation over platinum gives $C_{7} H_{16}$ . The parent hydrocarbon adds bromine and also reacts with $[A g (N H_{3})_{2}] O H$ to give a precipitate. The parent hydrocarbon is

$(C H_{3})_{3} CC H_{2} C \equiv C H$

$C H_{3} C H = C H C H_{2} C H = C H_{2}$

$C H_{3} C H_{2} C \equiv C H C H (C H_{3})_{2}$

$C H_{3} C H = C H C H = C H C H_{3}$

Correct answer is (a) $(C H_{3})_{3} CC H_{2} C \equiv C H$

Q. A hydrocarbon of molecular formula C7​H12​ on catalytic hydrogenation over platinum gives C7​H16​. The parent hydrocarbon adds bromine and also reacts with [Ag(NH3​)2​]OH to give a precipitate. The parent hydrocarbon is

(CH3​)3​CCH2​C≡CH

CH3​CH=CHCH2​CH=CH2​

CH3​CH2​C≡CHCH(CH3​)2​

CH3​CH=CHCH=CHCH3​