Question

A hydrocarbon has carbon and hydrogen. Its molecular weight is 28. Its possible formula would be

• A. $C_3{H}_6$
• B. $C_2{H}_4$
• C. $C{H}_4$
• D. $C_4{H}_8$

Answer 1

Answer: (B)

Componds	molecular
$C_3{H}_6$	$12\times 3+6=42$
$C_2{H}_4$	$12\times 2+4=28$
$C{H}_4$	$12+4=16$
$C_4{H}_8$	$12\times 4+8=56$

Hence, the formula of the given compound is $C_2{H}_4$.