A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. Identify the hydrocarbon.

Question

A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. Identify the hydrocarbon. (A) H2C = CH - CH2-CH2-CH3 (B)  (C)  (D) None of these

Tardigrade Admin · Accepted Answer

Since a single monochloro derivative is formed, so all the H-atoms in the compound must be equivalent. Therefore, the compound is

Q. A hydrocarbon $C_{5} H_{10}$ does not react with chlorine in dark but gives a single monochloro compound $C_{5} H_{9} Cl$ in bright sunlight. Identify the hydrocarbon.

$H_{2} C = C H - C H_{2} - C H_{2} - C H_{3}$

None of these

Since a single monochloro derivative is formed, so all the $H$ -atoms in the compound must be equivalent. Therefore, the compound is

Q. A hydrocarbon C5​H10​ does not react with chlorine in dark but gives a single monochloro compound C5​H9​Cl in bright sunlight. Identify the hydrocarbon.

H2​C=CH−CH2​−CH2​−CH3​

None of these

Since a single monochloro derivative is formed, so all the H-atoms in the compound must be equivalent. Therefore, the compound is

Q. A hydrocarbon $C_{5} H_{10}$ does not react with chlorine in dark but gives a single monochloro compound $C_{5} H_{9} Cl$ in bright sunlight. Identify the hydrocarbon.

$H_{2} C = C H - C H_{2} - C H_{2} - C H_{3}$

Since a single monochloro derivative is formed, so all the $H$ -atoms in the compound must be equivalent. Therefore, the compound is