A hydrocarbon (A) CnH2 n - 4 on ozonolysis gives (C H3)2CHCH2CHO,OHCCH2CH2CHO and CH3COCH3 . The value of n is

Question

A hydrocarbon (A) CnH2 n - 4 on ozonolysis gives (C H3)2CHCH2CHO,OHCCH2CH2CHO and CH3COCH3 . The value of n is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Based on the formula of hydrocarbon CnH2 n - 4 the degree of unsaturation is 3. So, there is two case: (I) 3 double bonds (II) 1 double bond and 1 triple bond Second case can be easily rejected because products of ozonolysis are aldehyde or ketone rather than carboxylic acid. So the alkene would be: ( CH 3)2 CHCH 2 CH = CHCH 2 CH 2 CH = CHCH 2 CH 2 CH = C ( CH 3)2 Which on ozonolysis will give products as: ( CH 3)2 CHCH 2 CH = CHCH 2 CH 2 CH = CHCH 2 CH 2 CH = C ( CH 3)2 underset substack text Ozonolysis arrow( CH 3)2 CHCH 2 CHO +2 OHCCH 2 CH 2 CHO + CH 3 COCH 3

Q. A hydrocarbon (A) Cn​H2n−4​ on ozonolysis gives (CH3​)2​CHCH2​CHO,OHCCH2​CH2​CHO and CH3​COCH3​ . The value of n is

Q. A hydrocarbon $(A)$ $C_{n} H_{2 n - 4}$ on ozonolysis gives
$(C H_{3})_{2} C H C H_{2} C H O, O H CC H_{2} C H_{2} C H O$ and $C H_{3} COC H_{3}$ .
The value of n is