Question

A hydrocarbon (A) $\left(C_8{H}_{10}\right)$ (E) is a steam volatile compound and on nitration gives two mononitro derivatives. (A) gives the following reactions. Compound (C) is:

• A.
• B.
• C.
• D.

Answer 1

Answer: (C)

D.U. in $(A)=\frac{\left(2n_C+2\right)-n_H}{2}=\frac{(8\times 2+2)-10}{2}=4^{\circ }$
$4D.U$. and $C:H\approx 1:1$ suggest that $(A)$ contains benzene ring with two extra $C$ atoms [i.e., two (Me) groups]. Since compound (A) is steam volatile and on nitration gives two nitro-derivatives, so (A) is ortho-xylene.