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Question
Physics
A force vecF=(40 hati+10 hatj) N acts on a body of mass 5 kg. If the body starts from rest, its position vector vecr at time t=10 s, will be:
Q. A force
F
=
(
40
i
^
+
10
j
^
)
N
acts on a body of mass
5
k
g
. If the body starts from rest, its position vector
r
at time
t
=
10
s
, will be:
985
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JEE Main 2021
Laws of Motion
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A
(
100
i
^
+
400
j
^
)
m
4%
B
(
100
i
^
+
100
j
^
)
m
2%
C
(
400
i
^
+
100
j
^
)
m
90%
D
(
400
i
^
+
400
j
^
)
m
4%
Solution:
d
t
d
v
=
a
=
m
F
=
(
8
i
^
+
2
j
^
)
m
/
s
2
d
t
d
r
=
v
=
(
8
t
i
^
+
2
t
j
^
)
m
/
s
r
=
(
8
i
^
+
2
j
^
)
2
t
2
m
At
t
=
10
sec
r
=
[(
8
i
^
+
2
j
^
)
50
]
m
⇒
r
=
(
400
i
^
+
100
j
^
)
m