A homogeneous ideal gaseous reaction AB 2( g ) leftharpoons A ( g )+2 B ( g ) is carried out in a 25 litre flask at 27° C. The initial amount of AB 2 was 1 mole and the equilibrium pressure was 1.9 atm The value of K P is x × 10-2 The value of x is .(Integer answer)

Question

A homogeneous ideal gaseous reaction AB 2( g ) leftharpoons A ( g )+2 B ( g ) is carried out in a 25 litre flask at 27° C. The initial amount of AB 2 was 1 mole and the equilibrium pressure was 1.9 atm The value of K P is x × 10-2 The value of x is .(Integer answer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/b4823cf21d5bb0944ea94f8b22480f46-.png" /> 1.9 × 25= n T × 0.08206 × 300 n T =1.93=1+2 α α=0.465 Kp =(((0.465/1.93) × 19)((0.93/1.93) × 1.9)2/((0.535)1.93 × 1.9)) ≃ 73 × 10-2 atm 2

Q. A homogeneous ideal gaseous reaction AB2(g)​⇌A(g)​+2B(g)​ is carried out in a 25 litre flask at 27∘C. The initial amount of AB2​ was 1 mole and the equilibrium pressure was 1.9atm The value of KP​ is x×10−2 The value of x is _____.(Integer answer)

1.9×25=nT​×0.08206×300 nT​=1.93=1+2α α=0.465 Kp=(1.930.535​×1.9)(1.930.465​×19)(1.930.93​×1.9)2​ ≃73×10−2atm2

$1.9 \times 25 = n_{T} \times 0.08206 \times 300$

$n_{T} = 1.93 = 1 + 2 α$

$α = 0.465$

$K p = \frac{( \frac{0.465}{1.93} \times 19 ) ( \frac{0.93}{1.93} \times 1.9 ) ^{2}}{( \frac{0.535}{1.93} \times 1.9 )}$

$≃ 73 \times 1 0^{- 2} a t m^{2}$