A hollow cylinder has a charge q coulomb within it. If φ is the electric flux in units of voltmeter associated with the curved surface B, the flux linked with the plane surface A in units of voltmeter will be-

Question

A hollow cylinder has a charge q coulomb within it. If φ is the electric flux in units of voltmeter associated with the curved surface B, the flux linked with the plane surface A in units of voltmeter will be- (A) ( q /2 ϵ0) (B) (φ/3) (C) ( q /ϵ0)-φ (D) (1/2)(( q /ϵ0)-φ)

Tardigrade Admin · Accepted Answer

φ text total =φ text curved +φ text plane surfaces =( q /ϵ0) φ+2 φ A -( q /ϵ0) ⇒ φ A -(1/2)(( q /ϵ0)-φ)

Q. A hollow cylinder has a charge $q$ coulomb within it. If $ϕ$ is the electric flux in units of voltmeter associated with the curved surface $B$ , the flux linked with the plane surface $A$ in units of voltmeter will be-

$\frac{q}{2 ϵ _{0}}$

$\frac{ϕ}{3}$

$\frac{q}{ϵ _{0}} - ϕ$

$\frac{1}{2} (\frac{q}{ϵ _{0}} - ϕ)$

$ϕ_{total} = ϕ_{curved} + ϕ_{plane surfaces} = \frac{q}{ϵ _{0}}$
$ϕ + 2 ϕ_{A} - \frac{q}{ϵ _{0}}$
$\Rightarrow ϕ_{A} - \frac{1}{2} (\frac{q}{ϵ _{0}} - ϕ)$

Q. A hollow cylinder has a charge q coulomb within it. If ϕ is the electric flux in units of voltmeter associated with the curved surface B, the flux linked with the plane surface A in units of voltmeter will be-

2ϵ0​q​

3ϕ​

ϵ0​q​−ϕ

21​(ϵ0​q​−ϕ)