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Tardigrade
Question
Chemistry
(A) HOCl + H 2 O 2 arrow H 3 O ++ Cl -+ O 2 (B) I 2+ H 2 O 2+2 OH - arrow 2 I -+2 H 2 O + O 2 Choose the correct option.
Q. (A)
H
OCl
+
H
2
O
2
→
H
3
O
+
+
C
l
−
+
O
2
(B)
I
2
+
H
2
O
2
+
2
O
H
−
→
2
I
−
+
2
H
2
O
+
O
2
Choose the correct option.
2464
208
JEE Main
JEE Main 2021
Redox Reactions
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A
H
2
O
2
acts as reducing and oxidising agent respectively in equation (A) and (B)
24%
B
H
2
O
2
acts as oxidising agent in equation (A) and
(
B
)
26%
C
H
2
O
2
acts as reducing agent in equation (A) and
(
B
)
36%
D
H
2
O
2
act as oxidizing and reducing agent respectively in equation (A) and (B)
14%
Solution:
(A)
H
OCl
+
H
2
O
2
→
H
3
O
+
+
C
l
−
+
O
2
In this equation,
H
2
O
2
is reducing chlorine from +1 to -1
(B)
I
2
+
H
2
O
2
+
2
O
H
−
→
2
I
−
+
2
H
2
O
+
O
2
In this equation,
H
2
O
2
is reducing iodine from 0 to
−
1
In (A) reduction of HOCl occurs so it will be a oxidising agent hence
H
2
O
2
will be a reducing agent.
In
(
B
)
reduction of
I
2
occurs so it will be a oxidising agent and
H
2
O
2
will be a reducing agent.