A hiker stands on the edge of a cliff 490 m above the ground and throws a stone horizontally with a speed of 15 ms-1. The time taken by the stone to reach the ground is

Question

A hiker stands on the edge of a cliff 490 m above the ground and throws a stone horizontally with a speed of 15 ms-1. The time taken by the stone to reach the ground is (A) 5 s (B) 10 s (C) 12 s (D) 15 s

Tardigrade Admin · Accepted Answer

Here, u = 15 m s-1, h = 490 m Time taken by the stone to reach the ground is t=√(2h/g) =√(2×490 m/9.8 ms-2) =10 s

Q. A hiker stands on the edge of a cliff $490 m$ above the ground and throws a stone horizontally with a speed of $15 m s^{- 1}$ . The time taken by the stone to reach the ground is

$5 s$

$10 s$

$12 s$

$15 s$

Here, $u = 15 m s^{- 1}$ ,
$h = 490 m$
Time taken by the stone to reach the ground is
$t = \frac{2 h}{g}$
$= \frac{2 \times 490 m}{9.8 m s ^{- 2}}$
$= 10 s$

Q. A hiker stands on the edge of a cliff 490m above the ground and throws a stone horizontally with a speed of 15ms−1. The time taken by the stone to reach the ground is

5s

10s

12s

15s