A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be

Question

A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be (A) doubled (B) four times (C) one-fourtth (D) halved

Tardigrade Admin · Accepted Answer

H1=(V2/R)t H2=(V2/R/2)t ∴ (H2/H1)=2 ⇒ H2=2H1

Q. A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be

doubled

four times

one-fourtth

halved

$H_{1} = \frac{V ^{2}}{R} t$
$H_{2} = \frac{V ^{2}}{R /2} t$
$∴ \frac{H _{2}}{H _{1}} = 2$
$\Rightarrow H_{2} = 2 H_{1}$

Q. A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be

doubled

four times

one-fourtth

halved

H1​=RV2​t H2​=R/2V2​t ∴H1​H2​​=2 ⇒H2​=2H1​

$H_{1} = \frac{V ^{2}}{R} t$
$H_{2} = \frac{V ^{2}}{R /2} t$
$∴ \frac{H _{2}}{H _{1}} = 2$
$\Rightarrow H_{2} = 2 H_{1}$