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Physics
A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be
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Q. A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be
AIEEE
AIEEE 2005
Current Electricity
A
doubled
36%
B
four times
13%
C
one-fourtth
12%
D
halved
39%
Solution:
$H_{1}=\frac{V^{2}}{R}t$
$H_{2}=\frac{V^{2}}{R/2}t$
$\therefore \frac{H_{2}}{H_{1}}=2$
$\Rightarrow H_{2}=2H_{1}$