A heat engine absorbs heat Q1 at temperature T1, and Q2 at temperature T2. Work done by the engine is (Q1 + Q2). This data:

Question

A heat engine absorbs heat Q1 at temperature T1, and Q2 at temperature T2. Work done by the engine is (Q1 + Q2). This data: (A) Violates first law of thermodynamics (B) Violates first law of thermodynamics if Q1 = -ve (C) Violates first law of thermodynamics if Q2 = - ve (D) Does not violates first law of thermodynamics

Tardigrade Admin · Accepted Answer

Some mechanical energy is always converted to other form of energy or total heat cannot be converted to useful work. This is first law of thermodynamics

Q. A heat engine absorbs heat $Q_{1}$ at temperature $T_{1}$ , and $Q_{2}$ at temperature $T_{2} .$ Work done by the engine is $(Q_{1} + Q_{2})$ . This data:

Violates first law of thermodynamics

Violates first law of thermodynamics if $Q_{1} = - v e$

Violates first law of thermodynamics if $Q_{2} = - v e$

Does not violates first law of thermodynamics

Some mechanical energy is always converted to other form of energy or total heat cannot be converted to useful work. This is first law of thermodynamics

Q. A heat engine absorbs heat Q1​ at temperature T1​, and Q2​ at temperature T2​. Work done by the engine is (Q1​+Q2​). This data:

Violates first law of thermodynamics

Violates first law of thermodynamics if Q1​=−ve

Violates first law of thermodynamics if Q2​=−ve

Does not violates first law of thermodynamics

Some mechanical energy is always converted to other form of energy or total heat cannot be converted to useful work. This is first law of thermodynamics

Q. A heat engine absorbs heat $Q_{1}$ at temperature $T_{1}$ , and $Q_{2}$ at temperature $T_{2} .$ Work done by the engine is $(Q_{1} + Q_{2})$ . This data:

Violates first law of thermodynamics if $Q_{1} = - v e$

Violates first law of thermodynamics if $Q_{2} = - v e$