A gun of mass 10 kg fires 4 bullets per second. The mass of each bullet is 20 g and the velocity of the bullet when it leaves the gun is 300 ms-1. The force required to hold the gun when firing is

Question

A gun of mass 10 kg fires 4 bullets per second. The mass of each bullet is 20 g and the velocity of the bullet when it leaves the gun is 300 ms-1. The force required to hold the gun when firing is (A) 6 N (B) 8 N (C) 24 N (D) 240 N

Tardigrade Admin · Accepted Answer

Momentum of one bullet, p = mv = 20 Ã 10-3 Ã 300 = 6 kg m s-1 N = number of bullet per sec = 4 â´ (dp/dt)= change of momentum per sec or force = N(p - 0) = 4 Ã 6 = 24 N

Q. A gun of mass 10 kg fires 4 bullets per second. The mass of each bullet is 20 g and the velocity of the bullet when it leaves the gun is 300 ms^-1. The force required to hold the gun when firing is

6 N

8 N

24 N

240 N

Momentum of one bullet, p = mv
= 20 × 10 $^{- 3}$ × 300 = 6 kg m s $^{- 1}$
N = number of bullet per sec = 4
$∴ \frac{d p}{d t} =$ change of momentum per sec or force
= N(p - 0) = 4 × 6 = 24 N

Q. A gun of mass 10 kg fires 4 bullets per second. The mass of each bullet is 20 g and the velocity of the bullet when it leaves the gun is 300 ms-1. The force required to hold the gun when firing is

6 N

8 N

24 N

240 N

Momentum of one bullet, p = mv = 20 × 10−3 × 300 = 6 kg m s−1 N = number of bullet per sec = 4 ∴dtdp​= change of momentum per sec or force = N(p - 0) = 4 × 6 = 24 N

Q. A gun of mass 10 kg fires 4 bullets per second. The mass of each bullet is 20 g and the velocity of the bullet when it leaves the gun is 300 ms^-1. The force required to hold the gun when firing is

Momentum of one bullet, p = mv
= 20 × 10 $^{- 3}$ × 300 = 6 kg m s $^{- 1}$
N = number of bullet per sec = 4
$∴ \frac{d p}{d t} =$ change of momentum per sec or force
= N(p - 0) = 4 × 6 = 24 N