A gun applies a force F on a bullet which is given by F = (100 - 0.5 105 × t )N. The bullet emerges out with speed 400 m/s-1. Then find out the impulse exerted till force on bullet becomes zero

Question

A gun applies a force F on a bullet which is given by F = (100 - 0.5 105 × t )N. The bullet emerges out with speed 400 m/s-1. Then find out the impulse exerted till force on bullet becomes zero (A) 0.2 N s (B) 0.3 N s (C) 0.1 N s (D) 0.4 N s

Tardigrade Admin · Accepted Answer

F = (100 - 0.5 Ã 105t)N Given F = 0 100 - 0.5 Ã 105t = 0 100 = 0.5 Ã 105t T = 2 Ã 10-3 sec I = ∫F dt I = displaystyle ∫02×10-3(100- 0.5 105 t)dt I=[100 t-(105/2)(t2/2)]02×10-3 I=[100×2×10-3-(105/4)×4×10-6] I=[2×10-1-10-1] I=10-1=0.1 N-s

Q. A gun applies a force F on a bullet which is given by F=(100−0.5105×t)N. The bullet emerges out with speed 400m/s−1. Then find out the impulse exerted till force on bullet becomes zero

0.2 N s

0.3 N s

0.1 N s

0.4 N s

F = (100 - 0.5 × 105t)N Given F = 0 100 - 0.5 × 105t = 0 100 = 0.5 × 105t T = 2 × 10-3 sec I = ∫F dt I = ∫02×10−3​(100- 0.5 105 t)dt I=[100t−2105​2t2​]0​​​2×10−3​ I=[100×2×10−3−4105​×4×10−6] I=[2×10−1−10−1] I=10−1=0.1 N-s

Q. A gun applies a force F on a bullet which is given by $F = (100 - 0.51 0^{5} \times t) N$ . The bullet emerges out with speed $400 m / s^{- 1}$ . Then find out the impulse exerted till force on bullet becomes zero