A guitar string is 90 cm long and has a fundamental frequency of 124 Hz. To produce a fundamental frequency of 186 Hz, the guitar should be pressed

Question

A guitar string is 90 cm long and has a fundamental frequency of 124 Hz. To produce a fundamental frequency of 186 Hz, the guitar should be pressed (A) 60 cm (B) 30 cm (C) 20 cm (D) 10 cm

Tardigrade Admin · Accepted Answer

Here, L1=90 cm, upsilon1=124 Hz, upsilon2=186 Hz, L2 =? According to the law of length, upsilon2L2= upsilon1L1 ∴ L2=( upsilon1L1/ upsilon2)=(124×90/186) =60 cm

Q. A guitar string is $90 c m$ long and has a fundamental frequency of $124 Hz$ . To produce a fundamental frequency of $186 Hz$ , the guitar should be pressed

$60 c m$

$30 c m$

$20 c m$

$10 c m$

Here, $L_{1} = 90 c m$ ,
$υ_{1} = 124 Hz$ ,
$υ_{2} = 186 Hz, L_{2}$ =?
According to the law of length, $υ_{2} L_{2} = υ_{1} L_{1}$
$∴ L_{2} = \frac{υ _{1} L _{1}}{υ _{2}} = \frac{124 \times 90}{186}$
$= 60 c m$

Q. A guitar string is 90cm long and has a fundamental frequency of 124Hz. To produce a fundamental frequency of 186Hz, the guitar should be pressed

60cm

30cm

20cm

10cm