A golf-ball weigh 40.0 g. If it is moving with a velocity of 20.0 ms-1, its de-Broglie wavelength is:

Question

A golf-ball weigh 40.0 g. If it is moving with a velocity of 20.0 ms-1, its de-Broglie wavelength is: (A)  1.66× 10-34nm (B)  8.28× 10-32nm (C)  8.28× 10-25nm  (D)  1.66× 10-24nm

Tardigrade Admin · Accepted Answer

From de-Broglie equation, λ =(h/m v) ∴ λ =(6.626 × 10-34 j . s /40 × 10-3 kg × 20.0 ms -1) =8.28 × 10-34 m =8.28 × 10-34 × 109 nm =8.28 × 10-25 nm

Q. A golf-ball weigh $40.0 g$ . If it is moving with a velocity of $20.0 m s^{- 1}$ , its de-Broglie wavelength is:

$1.66 \times 1 0^{- 34} nm$

$8.28 \times 1 0^{- 32} nm$

$8.28 \times 1 0^{- 25} nm$

$1.66 \times 1 0^{- 24} nm$

From de-Broglie equation,
$λ = \frac{h}{m v}$
$∴ λ = \frac{6.626 \times 1 0 ^{- 34} j . s}{40 \times 1 0 ^{- 3} k g \times 20.0 m s ^{- 1}}$
$= 8.28 \times 1 0^{- 34} m$
$= 8.28 \times 1 0^{- 34} \times 1 0^{9} nm$
$= 8.28 \times 1 0^{- 25} nm$

Q. A golf-ball weigh 40.0g. If it is moving with a velocity of 20.0ms−1, its de-Broglie wavelength is:

1.66×10−34nm

8.28×10−32nm

8.28×10−25nm

1.66×10−24nm