Question

A golf-ball weigh $40.0\,g$. If it is moving with a velocity of $20.0\,ms^{-1}$, its de-Broglie wavelength is:

• A. $ 1.66\times 10^{-34}nm$
• B. $ 8.28\times 10^{-32}nm$
• C. $ 8.28\times 10^{-25}nm $
• D. $ 1.66\times 10^{-24}nm $

Answer 1

Answer: (C)

From de-Broglie equation,
$\lambda =\frac{h}{m v}$
$\therefore \lambda =\frac{6.626 \times 10^{-34} j . s }{40 \times 10^{-3} kg \times 20.0\, ms ^{-1}}$
$=8.28 \times 10^{-34} m$
$=8.28 \times 10^{-34} \times 10^{9} nm$
$=8.28 \times 10^{-25} nm$