A glass slab of thickness 3 cm and refractive index 3/2 is placed on ink mark on a piece of paper. For a person looking at the mark at a distance 5.0 cm above it, the distance of the mark will appear to be

Question

A glass slab of thickness 3 cm and refractive index 3/2 is placed on ink mark on a piece of paper. For a person looking at the mark at a distance 5.0 cm above it, the distance of the mark will appear to be (A) 3.0 cm (B) 4.0 cm (C) 4.5 cm (D) 5.0 cm

Tardigrade Admin · Accepted Answer

The apparent depth of ink mark =( text Real depth /μ)=(3/3 / 2)=2 cm Thus person views mark at a distance =2+2=4 cm.

Q. A glass slab of thickness $3 c m$ and refractive index $3/2$ is placed on ink mark on a piece of paper. For a person looking at the mark at a distance $5.0 c m$ above it, the distance of the mark will appear to be

3.0 cm

4.0 cm

4.5 cm

5.0 cm

The apparent depth of ink mark
$= \frac{Real depth}{μ} = \frac{3}{3/2} = 2 c m$
Thus person views mark at a distance $= 2 + 2 = 4 c m$ .

Q. A glass slab of thickness 3cm and refractive index 3/2 is placed on ink mark on a piece of paper. For a person looking at the mark at a distance 5.0cm above it, the distance of the mark will appear to be