A given metal crystallizes out with a cubic structure having edge length of 361 pm. If there are four metal aotms in one unit cell, what is the radius of one atom?

Question

A given metal crystallizes out with a cubic structure having edge length of 361 pm. If there are four metal aotms in one unit cell, what is the radius of one atom? (A) 80 pm (B) 108 pm (C) 40 pm (D) 127 pm

Tardigrade Admin · Accepted Answer

FCC: r = (a/2 √2) = (361/2 × 1.4141) = 127 pm

Q. A given metal crystallizes out with a cubic structure having edge length of 361 pm. If there are four metal aotms in one unit cell, what is the radius of one atom?

80 pm

108 pm

40 pm

127 pm

$FCC : r = \frac{a}{2 2} = \frac{361}{2 \times 1.4141} = 127 pm$

Q. A given metal crystallizes out with a cubic structure having edge length of 361 pm. If there are four metal aotms in one unit cell, what is the radius of one atom?

80 pm

108 pm

40 pm

127 pm

FCC: r=22​a​=2×1.4141361​=127 pm

$FCC : r = \frac{a}{2 2} = \frac{361}{2 \times 1.4141} = 127 pm$