A given charge is situated at a certain distance from an electric dipole in the end on position experience a force F. If the distance of the charge is doubled, the force acting on the charge will be

Question

A given charge is situated at a certain distance from an electric dipole in the end on position experience a force F. If the distance of the charge is doubled, the force acting on the charge will be (A) zero (B)  F/2  (C)  F/4  (D)  F/8

Tardigrade Admin · Accepted Answer

The intensity on axis line of dipole at any point E=(1/4π ε 0).(2p/d3) F=qE =(2qp/4π ε 0.d3) or F propto (1/d3) The force at distance 2d from centre F'=( (d/2d) )3F F'=(F/8)

Q. A given charge is situated at a certain distance from an electric dipole in the end on position experience a force F. If the distance of the charge is doubled, the force acting on the charge will be

zero

$F /2$

$F /4$

$F /8$

The intensity on axis line of dipole at any point
$E = \frac{1}{4 π ε _{0}} . \frac{2 p}{d ^{3}}$
$F = qE$ $= \frac{2 qp}{4 π ε _{0} . d ^{3}}$
or $F \propto \frac{1}{d ^{3}}$
The force at distance 2d from centre
$F^{'} = (\frac{d}{2 d})^{3} F$
$F^{'} = \frac{F}{8}$