A giant refracting telescope at an observatory has an objective lens of focal length 15 m. If an eye piece of focal length .0 cm is used, what is the angular magnification of the telescope?

Question

A giant refracting telescope at an observatory has an objective lens of focal length 15 m. If an eye piece of focal length .0 cm is used, what is the angular magnification of the telescope? (A) 1000  (B) 1500 (C) 2000  (D) 3000

Tardigrade Admin · Accepted Answer

Here, f0 = 15 m = 15 × 102 cm, fe = 1.0 cm ∴ magnification, m = (f0/fe) = (15× 102/1) = 1500

Q. A giant refracting telescope at an observatory has an objective lens of focal length $15 m$ . If an eye piece of focal length $.0 c m$ is used, what is the angular magnification of the telescope?

$1000$

$1500$

$2000$

$3000$

Here, $f_{0} = 15 m = 15 \times 1 0^{2} c m$ ,
$f_{e} = 1.0 c m$
$∴$ magnification, $m = \frac{f _{0}}{f _{e}}$
$= \frac{15 \times 1 0 ^{2}}{1} = 1500$

Q. A giant refracting telescope at an observatory has an objective lens of focal length 15m. If an eye piece of focal length .0cm is used, what is the angular magnification of the telescope?

1000

1500

2000

3000